[ltp] Showkeys -s

[ZeiMoT]

Running
showkey -s
and then pressing and releasing the left shift button
gives:
0x2a 0xaa

Holdning the left shift a little longer before releasing gives a lot of
0x2a ended with a 0xaa

Well, I tried to Press the Thinkpad, the Volume- Volume+ and the Mute
buttons, as expected, they gave no response.

Holding the shift key down and then pressing the thinkpad button gave the
same result as pressing and releasing the shift key. The same goes with
the Volume- Volume+ and Mute buttons.

Oh, so those keys interfere with the keyboard presses, thus, one might
think that they are really keys that affects the keyboard scancodes but
not in a way that we know how to read, right?

But why does the pressing-left-shift and thinkpad button produce a
leftshiftpress and a leftshiftrelease? and then when I release the
leftshiftkey it produces a leftshiftkeyrelease scancode: 0xaa . ?

Is it possible that IBM has made a new set of Double scancodes that is not
take in to count by the kernel? Are there any scancode values that are not
read by the kernel?

  -=< ZeiMoT >=-

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